Question

A poster is on top of the building. Rajesh is standing on the ground at a distance of 50m from the building. the angles of elevations to the top of the poster and bottom of the poster are 45 degree and 30 degree respectively. what is the height of the poster?

Answer 1

Step-by-step explanation:

inΔPNQ,tan45∘=PQ/NQ

∴PQ=NQ=50min

ΔMNQ,tan30∘=MQNQ

∴13–√=MQ50∴MQ=503–√

∴h=PM

=PQ−MQ

=50−503–

√=503–√(3–√−1)

 

∴ Poster height = 503–√3–√−1)

if u want ill work out n show u

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