Question

A posve mber is 5 time another umber. If 21 is aded to both the umbers, then one of the new umbers become twie of other new umbers. Find the orgnal umbers ?

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Answer 1

Answer:

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Answer 2

Corrected Question :

• A positive number is 5 time another number. If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers. Find the original numbers ?

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Given : A positive number is 5 time another number and 21 is added to both the numbers. then one of the new numbers become twice of other new numbers.

To Find : The original numbers ?

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❍ Let's consider the other number be a

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Therefore,

• Positive number

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Given that,

• A positive number is 5 times another number.

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$~~~~~~~~~~{\sf:\implies{Positive~ number ~5~ ~× ~Other ~number}}$

$~~~~~~~~~~{\sf:\implies{Positive~ number~ = ~5 ~×~ a}}$

$~~~~~~~~~~{\sf:\implies{Positive ~number~=~5a}}$

$~~~~~~~~~~:\implies{\underline{\boxed{\frak{\pink{Positive number~=~5a}}}}}$★

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$\underline{\frak{According~ to~ the ~Given~ Question~:}}$

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• If 21 is added to both the numbers, then one of the new numbers become twice of other new numbers.

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$~~~~~~~~~~{\sf:\implies{21~+~Positive~number~=~2~(Other ~number~+~21)}}$

$~~~~~~~~~~{\sf:\implies{21 ~+ ~5a~ = ~2(a~ + ~21)}}$

$~~~~~~~~~~{\sf:\implies{21~+~5a~=~2a~+~42}}$

$~~~~~~~~~~{\sf:\implies{5a~=~2a~+~42~-~21}}$

$~~~~~~~~~~{\sf:\implies{5a~=~2a~+~21}}$

$~~~~~~~~~~{\sf:\implies{5a~-~2a~=~21}}$

$~~~~~~~~~~{\sf:\implies{3a~=~21}}$

$~~~~~~~~~~{\sf:\implies{a~=~\dfrac{21}{3}}}$

$~~~~~~~~~~{\sf:\implies{a~=~\cancel\dfrac{21}{3}}}$

$~~~~~~~~~~{\sf:\implies{a~=~7}}$

$~~~~~~~~~~:\implies\underset{\blue{\rm Required\ Answer}}{\underbrace{\boxed{\frak{\pink{a~=~7}}}}}$

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Therefore,

• Here, a denotes Other number which is 7 & The Positive number is 5a = 5 × 7 = 35.

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Hence,

$\therefore\underline{\sf{The~numbers ~are~\bf{7}~\sf{\&}~\bf{35}}}$