Question

A pot of depth 10 cm is filled with the liquid, due to this its base appears to be raised by 2 cm up from its original position, find the refractive index of the liquid.​

Answer 1

Refractive Index

Refractive index is defined as the ratio of real depth to apparent depth.

It can  be represented as,

$\mu=\frac{Real \ depth}{Apparent \ depth}$

Where,μ is refractive index of liquid.

Real Depth: It is the actual depth at the bottom of the tank.

Apparent Depth: It is the virtual depth observed as a result of refraction of light. It depends on the refractive index of the medium.

According to information given in the question,

real depth $= 10 \ cm$

apparent depth $= (10-2)=8 \ cm$

So, refractive index (μ)= $\frac{10}{8}=1.25$

So, the refractive index of the liquid inside the pot is 1.25.