A potential difference applied on X ray tube is 5V and the current through it is 3.2mA.Then the no. of electrons striking the target per secomd is
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Answered by
6
ne=It
ne=It
⇒
n
t
=
I
e
=
3.2×
10
−3
1.6×
10
−19
=2×
10
6
⇒nt=Ie=3.2×10−31.6×10−19=2×106

ne=It
⇒
n
t
=
I
e
=
3.2×
10
−3
1.6×
10
−19
=2×
10
6
⇒nt=Ie=3.2×10−31.6×10−19=2×106

Answered by
1
on :
n=Iten=Ite
=3.2×10^−3×1÷1.6×10^−19
=2×10^16
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Praneeth331:
thanks
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