Question

A potential difference applied on X ray tube is 5V and the current through it is 3.2mA.Then the no. of electrons striking the target per secomd is

Answer 1

ne=It

ne=It

⇒

n

t

=

I

e

=

3.2×

10

−3

1.6×

10

−19

=2×

10

6

⇒nt=Ie=3.2×10−31.6×10−19=2×106



Answer 2

on :

n=Iten=Ite

=3.2×10^−3×1÷1.6×10^−19

=2×10^16

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