Question

A potential difference of 10 V is applied across a conductor of 1000 ohm. The number of electrons flowing through the conductor in 300 s is....?? Plllzzz repllyy fast!

Answer 1

V=IR
I=0.01
I=q/t
q=3Coulumb or 3/1.6*10^-19 electrons
1.875*10^19 electrons
 
Hope it's help you

Answer 2

Answer:

Charge, n = 1.87 × 10¹⁹.

Explanation:

It is given that,

Potential difference across the conductor, V = 10 V

Resistance of the conductor, R = 1000 ohms

We have to find the number of electrons flowing through the conductor in 300 s. Mathematically, it can be written as :

$I=\dfrac{q}{t}$

q = I × t

From Ohm's law, $V=IR$

$I=\dfrac{V}{R}$

So, $q=\dfrac{V\times t}{R}$

$q=\dfrac{10\times 300}{1000}$

q = 3 C

Also, q = n e

n is number of electrons

$n=\dfrac{q}{e}$

$n=\dfrac{3}{1.6\times 10^{-19}}$

$n=1.87\times 10^{19}$

Hence, the number of electrons flowing through the conductor in 300 s is 1.87 × 10¹⁹.