Question

a potential difference of 10V is applied across a conductor of resistance 1Kohm find the number of electrons flowing through the conductor in 5 minutes​

Answer 1

Answer :

• Potential Difference = 10 V
• Resistance = 1000 Ω
• Time = 5×60 = 300 sec
• Number of electrons flowing through = ?

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$\underline{\bigstar{\textsf{According to the Question :}}}$

$:\implies\sf q = ne$

$:\implies\sf n = \dfrac{q}{e}$

$\qquad\quad\small\dag\sf n = Number \ of \ electrons$

Formulas to be used :

$\dag\:\sf q = I \times t$

$\dag\:\sf I = \dfrac{V}{R}$

So now,

$:\implies\sf n = \dfrac{q}{e}$

$:\implies\sf n = \dfrac{V\times t}{R \times e}$

$:\implies\sf n = \bigg\lgroup \dfrac{10\times 300}{1000\times 1.6\times 10^{-19}}\bigg\rgroup$

$:\implies\sf n = \bigg\lgroup \dfrac{3000}{1.6\times 10^{-16}}\bigg\rgroup$

$:\implies\underline{\boxed{\pink{\mathfrak{n = 1.875\times 10^{-19}}}}}$

Answer 2

Given:-

$\bigstar$The potential difference is 10 V

$\:$

$\bigstar$The conductor of resistance is 1k ohm

$\:$

$\bigstar$The time that electrons flowing through the conductor is 5 minutes

$\:$

To Find:-

$\:$

$\bigstar$The no of electrons flowing through the conductor in 5 minutes ?..

$\:$

Solution:-

$\:$

$\bigstar$The potential difference is 10 V

$\:$

$\bigstar$The conductor of resistance is 1k ohm - 1000 ohm

$\:$

$\bigstar$The time that electrons flowing through the conductor is 5 minutes - 5 × 60 = 300 seconds

$\:$

$\bigstar$n = No of electrons

$\:$

$\bigstar$Using formula,

$\:$

$\\ \leadsto{ \boxed{ \boxed{ \boxed{ \bold{n = \frac{V \times t}{R \times e} }}}}}$

$\\ \leadsto { \boxed{ \boxed{ \boxed{ \bold{n = \frac{10 \times 300}{1000\times 1.6 \times {10}^{ - 19} } }}}}}$

$\\ \leadsto { \boxed{ \boxed{ \boxed{ \bold{n = \frac{ 3000}{1.6 \times {10}^{ - 16} } }}}}}$

$\\\leadsto{ \underline{ \boxed{ \boxed{ \boxed{ \bold{ \red{n = 1.875 \times 10 {}^{ - 19} }}}}}}}$