Question

A potential difference of 12 v is applied across conductor of length 0.2m if the drift velocity of electrons is 3*10^-4m calculate electron Mobility?​

Answer 1

Answer:

0.5 ×$10^{-5}$  0r  5×$10^{-6}$$m^{2} V^{-1} s^{-1}$

Explanation:

Given Data:

Potential difference =V =12v

Length=0.2m

Vd=3×$10^{-4}$m

Find out:

Mobility of electrons =μ=?

E=v/d =12/0.2=60Vm-1

μ=Vd/E

μ=3×$10^{-4}$m/60

μ=0.5 ×$10^{-5}$  0r 5×$10^{-6}$ $m^{2} V^{-1} s^{-1}$