Physics, asked by rupinderkaur8977, 1 year ago

A potential difference of 1200 V is established between two parallel plates of a capacitor. The plates of the capacitor are at a distance of 2cm apart. An electron is released from the negative plate at the same instant a proton is released from the positive end. How does the following:

a) velocity

b) Energy compare when they strike the opposite plates.

c) How far from the positive plate will the pass each other?

ANS: a) 42.84, b) equal, c)2.7cm

Answers

Answered by Offishjay
2
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