A potential difference of 20 volts applied to the ends
of a column of N AgNO3 solution, 4 cm in diameter
10
and 12 cm in length, gives a current of 1.198 amperes.
Calculate the specific and equivalent conductivity of
the solution.
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A potential difference of 20 volts applied to the ends of a column of M/10 AgNO3 solution, 4 cm in diameter and 12 cm in length gave a current of 0 2 ampere Calculate the specific and molar conductivities of the solution ... 4 × 10 - 4 Ω - 1 cm - 1 and Molar conductivity , λ m = κ × 1000 M or , λ m = 95
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