Question

A potential difference of 200 V is maintained across a conductor of resistance 100 . Ω The number of

electrons flowing through it in one second is​

Answer 1

Answer:

n=1.25*10²⁰

Step-by-step explanation:

Voltage     =200V

Resistance=100Ω

V=IR

I=V/R

=200/100=2A

I=ne/t

n=It/e

n=2*1/1.6*10⁻¹⁹

n=20/16*10⁻²⁰

n=20*10²⁰/16

n=1.25*10²⁰

Answer 2

We are given,

the potential difference across a conductor is 200V

the resistance is 100Ω

We need to find,

the number of electrons flowing through the conductor in 1 second.

Solution,

potential difference = 200V

resistance =  100Ω

by Ohm's law,

$V=IR\\\\I=\frac{V}{R}$ is the current flowing through the conductor.

substituting,

$I=\frac{200}{ 100}\\\\I= 2A$

hence a current of 2A is flowing through the conductor.

now we know,

$I=\frac{ne}{t}$

substituting, and finding 'n'

$2= \frac{n*1.6*10^{-19} }{1}$

calculating n,

$n= \frac{2*1}{1.6*10^{-19} }$

∴ n= $\frac{20}{16*10^{-20} }$

n= 1.25x10²⁰

THEREFORE THE NUMBER OF ELECTRONS FLOWING THROUGH THE CONDUCTOR IN 1 SECOND IS n= 1.25x10²⁰.