Question

a potential difference of 20kV is applied across an x-tube find the minimum wavelength of x-ray genrated ​

Answer 1

Answer:

The minimum wavelength of x-ray genrated would be

$= 6.2 \times {10}^{ - 13} m = 0.6 \: picometer$

Explanation:

The relation between wavelength of x-rays produced to that of applied voltage is given as

$wavelength = \frac{1.24 \times {10}^{ - 8} }{voltage}$

HENCE wavelength of the x-rays

$\frac{1.24 \times {10}^{ - 8} }{20 \times {10}^{3} } = 0.62 \times {10}^{ - 13} m$