a potential difference of 220 volts is applied across a resistance of 440 ohms in an electric iron calculate the power of the circuit
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Answered by
12
P,= V^2/R
P=(220*220)/440
=110
P=(220*220)/440
=110
Answered by
18
Given: V=220v, R=440ohms,P=?
P=VI
P=V(V/R).......ohms law V=IR
P=V^2/R
P=220X220 / 440
P=110W
P=VI
P=V(V/R).......ohms law V=IR
P=V^2/R
P=220X220 / 440
P=110W
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