a potential difference of 3 volt is applied across the conductor of resistance 1.5 volt calculate the number of electrons flowing through it in 1sec
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p. d accross r=3v
r=1. 5ohm
I=pd/r=3/1.5= 2
we know that,
I=Q/t
2=Q/1
Q=2couloumb
no. of electron flows per second=2×no. of electron constituting 1 coulomb charge
2×6. 25×10^18=12.5×10^18
r=1. 5ohm
I=pd/r=3/1.5= 2
we know that,
I=Q/t
2=Q/1
Q=2couloumb
no. of electron flows per second=2×no. of electron constituting 1 coulomb charge
2×6. 25×10^18=12.5×10^18
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