Question

A potential difference of 4 volts is applied to 2 resistors of 6 ohm and 2 ohm connected in series. Calculate:

a) the combined resistace

b) the current flowing

c) the p.d. across the 6 ohm resistor

Answer 1

a) the combined resistance is    6 ohm + 2 ohm     .......(in series)

                                      that is    8 ohm



b)  potential difference = 4 V

     current flowing = I = V/R          ................  (from V=I/R    by ohm's law)

                                  = 4/8

                                  = 0.5 A

c) potential difference across 6 ohm resistor =

           V = I/R                                                        .......(by ohm's law)

              = 0.5 / 6
             
              = 0.083 V




:)