Question

A potential difference of 4v is applied to two resistors of 6 ohm and 2 ohm connected in series calculate. a. the combined resistance, b. the current flowing, c. the potential different across 6 ohm resistor​

Answer 1

Answer:

a) Combined resistance = 8Ω

b) Current = $\pmb{\sf{ \dfrac{1}{2}}}$ Ampere

c) Potential difference across 6 ohm resistor = 3V

Explanation:

As per the provided information in the given question, we have :

• Total potential difference applied to two resistors = 4V
• Two resistors of 6Ω and 2Ω are connected in series.

★ Calculating the combined resistance :

As we know that,

When the resistors are connected in series combination, the combined or resultant resistance is given by the formula given below,

$\longrightarrow \sf { R_S = R_1 + R_2 + \dots R_n}$

Here,

• $\sf { R_1}$ = 6Ω
• $\sf { R_2}$ = 2Ω

Substituting values,

⇒ Combined resistance = 6Ω + 2Ω

⇒ Combined resistance = 8Ω ✰

$\therefore$ The combined resistance is 8Ω.

★ Calculating the current flowing (I) :

According to the Ohm's law, we know that :

$\longrightarrow \sf { V= IR}$

• V denotes potential difference
• I denotes current
• R denotes resistance

⇒ 4 = I × 8

⇒ $\sf \dfrac{4}{8}$ A = I

⇒ $\pmb{\sf{ \dfrac{1}{2}}}$ A = I ✰

$\therefore$ 1/2 Ampere of current is flowing in the circuit.

★ Calculating the potential difference across 6Ω resistor :

According to the Ohm's law, we know that :

$\longrightarrow \sf { V= IR}$

• Potential difference (V) = ?
• Current (I) = 1/2 A
• Resistance (R) = 6Ω

Substituting values,

⇒ V = ( $\sf \dfrac{1}{2}$ × 6 ) V

⇒ V = 3V ✰

$\therefore$ Potential difference across 6Ω resistor is 3V.