A potential difference,V=(1000±2)volt when applied across a resistance R1 gives a current I=(10±0.5)ampere.calculate the percentage error in R.given R=V÷I
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%error in V=(2÷1000)×100%=0.2%
%error in I=(0.5÷10)×100%=5%
thereore %error in R = 0.2%+5%
=5.2%
%error in I=(0.5÷10)×100%=5%
thereore %error in R = 0.2%+5%
=5.2%
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Answer:instead of 1000 it is 100 but you can solve like this....
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