Question

a potential difference V is applied between the terminals of a series combination of two capacitors of capacitance C1 and C2 if V1 and V2 are the potential difference across C1 and C2 respectively,then V1/V2 equals to​

Answer 1

Answer:

as given C

2

= 2C

1

.

parallel combination: C

e

q = 3C

1

Energy E =

2

1

* C

e

q * V

1

2

=

2

3

* C

1

* V

1

2

Series combination: C

e

q =

(C1+C2)

C1C2

=

3

2C

1

2

Energy E = 1/2 * 2/3 * C1 * V2² = 1/3 * C1 V2²

Equating energies, we get V1 : V2 = √2 : 3

Plot of energy vs Capacitance:

This will be linear if Voltage applied is assumed to be constant.