A potential of 120v is applied across the ends of a cylindrical copper rod of length 1cm and radius is 2.0mm. find the value of current through the rod . (The resistivity of copper is 1.7× 10-8 ohm m )
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Explanation:
I= V/R
R= 1.7×10^-8×1×10^-2/3.14×2×2×10^-6
0.13×10^-4
I= 120/0.13×10^-4
=923×10^4
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