Physics, asked by cutekhushicute5622, 1 year ago

A potential of 400v is applied to a capacitor ,the plates of which are 4mm apart.The strenghth of electric field is

Answers

Answered by dalipverma9017

0

Answer:

100kv/m

Explanation:

e=v/d

e=400/4

e=400×1000/4

e=100000 V/m

e=100kv/m

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