a potential of 5v is applied across a conductor of length 0.1m.The electric field developed in it is
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Resistivity of a material is given by ,
ρ=vdnelV
Given: V=5V,L=0.1m,vd=2.5×10−4m/s,n=8×1028m−3
therefore ρ=2.5×10−4×8×1028×1.6×10−19×0.15=1.56×10−5Ωm
Explanation:
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