Physics, asked by Achal2376, 8 months ago

A potentiometer circuit has been set up for finding the
internal resistance of a given cell. The main battery used
across the potentiometer wire, has an emf of 2.0 V and a
negligible internal resistance. The potentiometer wire itself
is 4m long, When the resistace R, connected across the
given cell, has values of
(i) infinity (ii) 9.5????

Answers

Answered by gyanendramahnar
0

Explanation:

Internal resistance of the unknown cell is

r(

l

2

l

1

−1)R=(

2.85

3

−1)(9.5Ω)=0.5Ω

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Answered by Parnabi
0

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