Physics, asked by suredhreddy036, 1 month ago

A potentiometer contains a cell of emf EO, internal resistance ro, a series resistance Rs and a uniform wire of length L and resistance RO in its primary circuit. Its secondary circuit contains a cell of emf E and internal resistance. R. varies with time (t) according to R =R. (1+at) (aisa +ve constant). The speed of jockey to keep the galvanometer of secondary circuit remain undeflected is​

Answers

Answered by aakhyapatel18jun2012
0

Answer:

Current in ABCD

I=

R

eq

V

=

r+r

1

V

potential difference across potentiometr =Ir

=

(r+r

1

)

Vr

Potential gradient =

L

V

=

(r+r

1

)

Vr

×

L

1

=k

we know that EMF=kl

l=balancing length

EMF=(

r+r

1

Vr

)

L

l

=(

r+r

1

ϵr

)

L

l

Answered by kiranchoudhary1107
1

Current in ABCD

I=

R

eq

V

=

r+r

1

V

potential difference across potentiometr =Ir

=

(r+r

1

)

Vr

Potential gradient =

L

V

=

(r+r

1

)

Vr

×

L

1

=k

we know that EMF=kl

l=balancing length

EMF=(

r+r

1

Vr

)

L

l

=(

r+r

1

ϵr

)

L

l

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