Question

A potentiometer wire 2m long has a resistance of 10Ω. It is connected in series with a cell of emf 4V and internal resistance 6Ω. Calculate the potential gradient along the wire in millivolt per millimetre.​

Answer 1

Answer:

when L=2m,R=10Ω,RE=990Ω,E=2V

Potential gradient of wire (k)

k=LV since I=R+ReE

V=IR=R+ReER=10+9902×10=100020

∴ V=2×10−2 volt

k=22×10−2

k=10−2V/m

k=0.01V/m

Explanation:

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Answer 2

Answer:

2.5 V/m

Explanation:

Given :

L = 2m

R = 10 ohm

r = 6 ohm

E = 4V

To find : Potential Gradient (K= V/L)

Formula:

V/L = ER/L(R+r)

Now it is just the matter of simple substitution :

V= 40/16

V = 2.5 V/m