Question

a potentiometer wire has a length of 2 metre and resistance 10 ohm it is connected in series with resistance 990 ohm and a cell of EMF 2 volt calculate the potential gradient along the wire

Answer 1

Explanation:

I = V / R

R = 990 + 10 = 1000 ohm

I = 2 / 1000 = 1/ 500 A

potential drop across the potentiometer = I x R

= 1/500 x 10 = 1/50V

potential gradient = pd / length = 1/ ( 50 x 2)

= 1/100 = 0.01 V/m