Question

A potentiometer wire has a length of 4m
to resistone of 5ohm what resistance
should be connected in series with a
- potentiometer wire f a cell of e.me
2v having internal resistance 2 to get
a potential gradient of 10-3 v/cm?​

Answer 1

Answer:

Explanation:

the total resistance after adding resistance R in series with potentiometer wire

=8Ω+RΩ

the current in the circuit will be

i=V/R

eq

​

=

R+8

2V

​

the potential drop across potentiometer wire will be iR

potentiometer

​

=

R+8

2V

​

×8

the potential gradient along length 4 m is given as

=V

p

​

otetiometer=

4

R+8

2V

​

×8

​

 

the gradient is given as 1mV/cm=.1V/m

4

R+8

2V

​

×8

​

=.1

R=32Ω