A potentiometer wire has length L. While calculating EMF of cell null point comes at L/4. If the area of cross section of potentiometer wire is doubled, then find the new null point.
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ANSWER = 1/2
Explanation:
Let x be the desired length.
Potential gradient in the first case = E0/ l
E=( 3/ l )⋅(E0/1 )=E0/3 (1)
Potential gradient in the second case.
= Eo /3l/2 = 2E0/ 3l
∴E=(x) 2E 0/3l (2)
From equations (i) and (ii), we get
E0/3 =(2E0/ 3l)x
⇒x= 1/2
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