Question

A poter holds a load of 500 N for 10second the work done by him

Answer 1

Work done by poter is 0J

This can be explained as:-

Work done, in terms of physics is defined only when the force applied causes some displacement. Simply holding a weight of no matter how much weight won't be counted as "work done" in physics even if the doer is tired. Since no displacement is produced s remains 0

So,

Work done = Fscos∅ = 500.0.cos0 = 0

Cheers!