A pouch has 7 red balls, 4 white balls and 5 blue balls of same size. If one ball is withdrawn from the pouch blindly, then what is the probability of ball not being white ?
Answers
Answered by
3
Step-by-step explanation:
m = 12 (Favorable Outcomes)
n = 16 (Total Outcomes)
Probability = m/n
= 12/16
= 3/4
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Answered by
2
Answer:
Since, total no. of balls = 5+7+4+2 = 18
(i) No. of balls that are white or blue = 5+2 = 7
∴ Required probability =
18
7
(ii) No. of balls that are red or black = 7+4 = 11
∴ Required probability =
18
11
(iii) No. of balls that are not white = 7+4+2 = 13
∴ Required probability =
18
13
(iv) No. of balls that are neither white nor black = 7+2 = 9
∴ Required probability =
18
9
=
2
1
Step-by-step explanation:
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