Question

a powder tin has a square base with side 12cm and height 17.5cm. another powder tin is cylindrical whose base diameter is 12cm and height is 17.5cm. which powder tin has more capacity and by how much?

Answer 1

Answer:

The tin with the square base has more capacity.

The difference is

$540.8cm^3$

Step-by-step explanation:

The  volume of the powder tin can be calculated using the formula

$V=l^2h$

where $l=12cm$ is the length of the square base and $h=17.5cm$ is the height.

The capacity of the powder tin is

$V_1=12^2\times 17.5cm^3$

$V_1=2520cm^2$

The volume of the cylindrical powder tin can also be calculated using the formula

$V=\pi r^2h$

where $r=\frac{12cm}{2}=6cm$ is the radius of the circular base and $h=17.5cm$ is the height.

$\Rightarrow V_2=\pi \times 6^2\times 17.5cm^3$

$\Rightarrow V_2=\pi 6^2\times 17.5cm^3$

$\Rightarrow V_2=1979.20cm^3$

Hence the tin with the square base has more capacity.

The difference is

$2520-1979.20=540.8cm^3$

Answer 2

Answer:

#anshika

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