Math, asked by satyam1747, 1 year ago

a powder tin has a square base with side 8 cm and height 13 cm. Another tin is cylindrical with radius of its base is 7 cm and height is 15 cm what of the two contains more powder. The difference of their capacity

Answers

Answered by Anonymous
38

  \bf \large \it {Hey  \: User!!!}

according to the question,

a powder Tim has a square base with side 8cm and height 13cm.

another cylindrical tin has radius 7cm and height 15cm.

we have to find out, which tin have more capacity. for that we have to find the volume of both tins.

>> the tin with square base has side 8cm and height = 13cm therefore it's a cuboidal tin and both breadth and length is 8cm.

volume of the cuboidal tin = l × b × h
= 8 × 8 × 13
= 64 × 13
= 832cm³

>> now the radius of the cylindrical tin is 7cm and height is 15cm.

volume of the cylindrical tin = πr²h
= 22/7 × 7 × 7 × 15
= 22 × 7 × 15
= 154 × 15
= 2310cm³

we can clearly see that volume of cylindrical tin is more.

hence, it's capacity must be also more than the cuboidal tin.

difference in the capacity = 2310 - 832
= 1478

the cylindrical tin has 1478m³ capacity more than the cuboidal one.

 \large \bf \it{Cheers!!!}



satyam1747: thank you sir
Anonymous: no worries sir :p
Answered by TooFree
48

Find the capacity of the square-base tin:

Volume = Length x Base x Height

Volume = 8 x 8 x 13 = 832 cm³


Find the capacity of the cylindrical base tin:

Volume = πr²h

Volume = π(7)²(15) = 2310 cm³


Find the difference in capacity:

Difference = 2310 - 832 = 1478 cm³


Answer: The difference is 1478 cm³

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