Physics, asked by arr7157, 5 months ago

A power source of 112 V is in series with two lamps that provide resistance of 12 and 16, respectively. What is the current through the circuit?
Group of answer choices

Answers

Answered by alisaqulain10

1

Answer:

let R1 = 12 and R2 = 16 , Given battery =112V

Rs = R1 + R2 = 12 +16 = 28 ohm

now according to ohm law

V=IR --- I = V/R = 112V / 28 = 4 ampere

Previous Question

Next Question

Similar questions

English, 2 months ago

Write a character sketch of the postmaster. Do you consider him selfish? Give reasons for your views.

Social Sciences, 2 months ago

name the smallest and lagest state in India in terms of area ...

Math, 2 months ago

2. if 3/4 of a number is12, then the number is *...

English, 5 months ago

1. Sum of the digits on the upper face is multiple of 5 Sample Space, S = {(1, 1), (1, 2), (1,3), (1,4), (1,5), (1, 6, (2, 1), (2, 2), (2,3), (2, 4), (2,5), (2, 6) (3, 1), (3, 2), (3, 32, (3, 4), (3,5 (3,6), (4, 1), (4,2), (4,3), (4,4), (4,5), (4,6) (5, 1), (5,2), (5,3), (5,4), (5,5), (5,6) (6, 1), (6,2), (6,3), (6,4), (6,5), (6, 6)}...

English, 5 months ago

why was Kezia afraid of her father??

Physics, 11 months ago

If R is the radius of earth , the height at which the weight of body becomes 1/4 its weight on the surface of the earth .............................

History, 11 months ago

Why did metternich describe mazzini as the dangerous enemy of our social order?

Science, 11 months ago

Describe the greenhouse effect.