Question

A power transmission line feeds input power at 2300 V to a step down transformer having 4000 turns in primary. What should be the number of turns in the secondary to get output power at 230 V?​

Answer 1

Answer:

$\huge\underline\orange{\mathcal Answer}$

$\huge{\mathcal Given}$

Ep = 2300 V

Np = 4000

Es = 230 V

Ns = ?

$\large{\mathcal {\frac{Es}{Ep}={\frac{Ns}{Np}}}}$

$\large{\mathcal Ns=Np×{\frac{Es}{Ep}}}$

$\large{\mathcal Ns=4000×{\frac{230}{2300}}}$

$\huge{\boxed{\mathcal Ns=400}}$

$\huge\orange{\mathcal Hope\:it\:helps!!!}$

Answer 2

SOLUTION

Given,

Input Power (Vp)= 2300V

Number of turns(n1)= 4000

Output power(Vs)=230V

$= > \frac{Vs}{Vp} = \frac{n2}{n1} \\ \\ Implies, \frac{230}{2300} = \frac{n2}{4000} \\ \\ = > n2 = \frac{1}{10} = \frac{n2}{4000} \\ \\ = > 10n2 = 4000 \\ \\ = > n2 = \frac{4000}{10} \\ \\ = > n2 = 400$

Therefore,

Number of turns in the secondary winding, n2= 400 turns.

Hope it helps ☺️