Question

A powerful motorcycle can accelerate from rest to 28 m/s in 4 seconds. What is its average acceleration? How far does it travel in that time?​

Answer 1

Answer:

$\huge\underline\mathrm{Solution}$

Given,

Starting Velocity u = 0 $\frac{m}{s}$

Each Velocity v = 28 $\frac{m}{s}$ in time t = 4 sec.

If acceleration = f

v= u+ft , 28= 0+ f × 4 , f = $\frac{28}{4}$ = 7 $\frac{m}{s²}$

Acceleration = $\frac{7m}{sec²}$

If distance travelled = S

S = ut + $\frac{1}{2ft²}$ = 0 × 4 + ( $\frac{1}{2}$ ) × 7 × 4² = 56 m

Distance travelled in 4 sec = 56 m

Hope it helps you :)

Answer 2

• Distance travelled in 4 sec = 56 m

Hafeez Contractor had nightmares that he was appearing for a maths test and he did not remember anything.