Question

A powitive number is divided into two parts such that the sum of tge squares of tge two parts is 208

Answer 1

let the numbers be x,y (x>y) here x2=18yaccording to the problemx2+y2=208....................(1) 18y+y2=208y2+18y-208=0 y2+26y-8y-208=0y(y+26)-8(y+26)=0 (y+26)(y-8)=0 as the numbers are +ve y-8=0 y=8 substitute y in (1) x2+(8)2=208 x2+64=208 x2=208-64x2=144 x=12 the nos. are 12,8