A PQR is right angled at Q and T is a point on PR such that QT perp PR If PR = 13 cm and RT = 4 cm , then QT =
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Given:
PQR is right angled
Q and T is a point on PR
QT ⊥ PR [From vertex Q to hypotenuse PR]
PR = 13 cm
RT = 4 cm
Find QT = ?
- Here PR = PT + RT
13 = PT + 4
PT = 13 - 4
PT = 9
- So by theorem
QT² = PT × RT
QT² = 9 × 4
QT² = 36
QT = 6cm
Hence the value of QT is 6 cm.
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