Question

A praticle of mass M at rest decays into two particle of masses m_1 and m_2, having non-zero velocities. The ratio of the de Broglie wavelength of the particles (lamda_1)/(lamda_2) is

Answer 1

Answer:

wavelength is inversely proportional to momentum

so

$\frac{lambda1}{lambda2} = \frac{m2v2}{m1v1}$

hope the answer will help you