Math, asked by zehabahmad7, 1 month ago

A president and a treasurer are to be chosen from a student club consisting of 50
people. How many different choices of officers are possible if
(a) there are no restrictions;
(b) A will serve only if he is president;
(c) B and C will serve together or not at all;
(d) D and E will not serve together?

Answers

Answered by rehanjaffer555
3

Answer:

Answer:

1) 2450

2) 2401

3) 2258

4) 192

Step-by-step explanation:

1) There are no restrictions:

For the first position we have 50 choices and 49 for the second, thus:

50 * 49 = 2450

or P(50,2)= \frac{50!}{(50−2)!} =50⋅49=2450P(50,2)=

(50−2)!

50!

=50⋅49=2450

2) A will serve only if he is a president

There two possibilities:

A will serve: C(49,1)= \frac{49!}{1!(49−1)!} =49C(49,1)=

1!(49−1)!

49!

=49

A will not serve: P(49,2)= \frac{49!}{(49−2)!} =49⋅48=2352P(49,2)=

(49−2)!

49!

=49⋅48=2352

thus 49 + 2352 = 2401

3) B and C will serve together or not at all:

B and C will serve together: 2!=22!=2

B will not serve and C will not serve: P(48,2)= \frac{48!}{(48−2)!} =48⋅47=2256P(48,2)=

(48−2)!

48!

=48⋅47=2256

thus 2 + 2256 = 2258

4) D and E will not serve together:

If D will be a president: 48

If D will be a treasurer: 48

If E will be a president: 48

If D will be a treasurer: 48

thus 48 + 48 + 48 + 48 = 192

Similar questions