Question

A pressure increase of 200n/cm^2 increased density of water by 0.1%. The bulk modulus of elasticity of water is equal to

Answer 1

Dear Student,

◆ Answer -

B = 2×10^9 N/m^2

● Explaination -

As we know volume is inversely proportional to density, volume will decrease by 0.1 % with increase in density by 0.1 %.

Bulk modulus of elasticity is -

B = stress / strain

B = (F/A) / (∆V/V)

B = -∆P / (∆V/V)

B = -200 / (-0.1/100)

B = 200×10^3

B = 2×10^5 N/cm^2

B = 2×10^9 N/m^2

Hope that helps you...