Question

A pressure of 20 N/m sq. is acting on a circular area of diameter 2 cm .find the normal force acting on circular area

Answer 1

Pressure = 20 N/m²

Diameter = 2 cm

Therefore, Radius = 1 cm.

∴ Area = πr² = 22/7 × (2/2)²

= 22/7 cm². = 22/7 × 10⁻⁴ m².

Now, Using the Formula,

Pressure = Force/Area

Therefore, Force = Pressure × Area

∴ Force = 20 × 22/7 × 10⁻⁴

∴ Force = 6.286 × 10⁻³ N.

Hope it helps.

Answer 2

Given, Pressure= 20N/m^2

Diameter= 2cm.

So, radius =( 2/2cm )= 1cm

Now, Remember=>>

(1) Pressure= Force/Area

=>Force= Pressure×Area

Now,

Area of circle= πr^2

{=22/7}×(1)^2

=>3.14cm^2

=>3.14 × 10^-4 m^2

(since 1cm^2= 10^-4m^2)

So,we get=>

Force= 20N/m^2×3.14 × 10^-4 m^2

=>Force = 6.28 × 10^-3 Newton.


thanks