Question

A pressure of 25 kPa is acting on an area of 25 m2.
a. Find the thrust acting on the said area
b. If the thrust acting is due to a cubical block of side 5 m, find the density of the material of the block.
c. Given that the acceleration due to gravity on Mars is 40% of that of the Earth, find the pressure the block would exert on the same area on Mars.​

Answer 1

Answer: Having in Mind that P = F/A

a)Given that P =25 KPa  = 25,000 Pa        A = 25 m2

Thus F = P.A = 25,000 Pa x 25 m2

F = 625,000 N

b)Pressure = density x gravity x height

 p = ρgh

ρ = p

    gh

ρ = 25,000 Pa

(9.8 m/s^2)( 5 m)

ρ = 510.20 Kg/m^3

c)  p = ρgh

p =  (510.20 Kg/m^3)(3.92 m/s^2)(5 m)

p = 9,999.92 Pa

p =10,000 Pa

Hope this Helps You Friend!

Explanation: