A prestressed concrete beam, 200mm wide and 300 mm deep, is prestressed with
wires (area = 320 mm) located at & constant eccentricity of 50 mm and carrying an
initial stress of 1000 N/mm². The span of the beam is 10m. Calculate the
percentage loss of stress in wires if (a) the beam is pre-tensioned and (b) the beam
is post-tensioned, using the following data: Es = 210 kN/mm and Ec = 35 kN/mm²;
relaxation of stress in steel 5 percent of the initial stress, shrinkage of concrete =
300 x 10-6 for pre tensioning and 200 x 10-6 for post tensioning; creep coefficient =
1.6; slip at anchorage 1 mm; frictional coefficient for wave effect = 0.0015 per
m.
Answers
Answer:
Longest question
Explanation:
Mark me as brainliest answer
Answer:
The answer is ,
The percentage loss of stress in wire due to pre-tensioned and post-tensioned is 22.33%
Explanation:
Given,
e = 50 mm
Area of cable = 320 mm²
Initial stress = 1000 Mpa
Length of Span (l) = 10m
Prestressing force P = 1000×320 = 320 kN
Es = 210 kN/mm
Ec = kN/mm²
Relaxation of stress in steel 5 percent of initial stress, Shrinkage of concrete for
Pre-tensioning= 300×
Post Tensioning = 200×
Creep coefficient = 1.6
Frictional coefficient for wave effect = 0.0015/m
Solution:
When beam is pretensioned,
Elastic deformation loss = m
m =
=
= 6
= +
= {(320× 10³)/ (200×300)} + {(320×10³×10⁵)/{(200×300³)/12}}
= 7.11 MPa
Elastic Deformation loss = 6×7.11
= 42.667 MPa
Shrinkage loss =
= (300×)×210×10³ MPa
= 63 MPa
Relaxation loss = × 1000
= 50 MPa
Creep loss = mθ
= 6 × 1.6 ×7.111
= 68.266 MPa
Total loss =223.333 MPa
% in loss = × 100
= 22.3 %
Answer : The percentage loss of stress in wires during the pre tensioned and post tensioned using the following data is 22.3%.
#SPJ3