A primary cell has an e.m.f. of 1.5 volt. When short-circuited
it gives a current of 3 ampere. The internal resistance of the
cell is
(a) 4.5 ohm (b) 2 ohm
(c) 0.5 ohm (d) (1/4.5) ohm
Answers
Answered by
3
Answer:
Explanation:
R = V/I = 0.5
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