Math, asked by bankarimansi99, 2 months ago

A principalof rupees 800 amount to rupees 1120 in 2 years . The rate of simple interest is :

Answers

Answered by Dikshayaduwanshi003
0

Q 1 - Adam borrowed some money at the rate of 6% p.a. for the first two years, at the rate of 9% p.a. for the next three years, and at the rate of 14% p.a. for the period beyond five years. If he pays a total interest of Rs. 11,400 at the end of nine years, how much money did he borrow?

A - 12,000

B - 13,000

C - 14,500

D - 12,500

Answer - A

Explanation

Let the sum borrowed be Z. Then,

(Zx6x2⁄100) + (Zx9x3⁄100) + (Zx14x4⁄100) = 11400

Therefore, 3Z⁄25 + 27Z⁄100 + 14Z⁄25) = 11400

? 95Z⁄100 = 11400

Z = (11400x100⁄95) = 12000

Q 2 - A certain sum of money amounts to Rs. 1008 in 2 years and to Rs. 1164 in 31⁄2 years. find the sum and the rate of interest?

A - Rs. 800, Rate 14%

B - Rs. 850, Rate 12%

C - Rs. 800, Rate 13%

D - Rs. 500, Rate 13%

Answer - C

Explanation

S.I. for 11⁄2years = Rs. (1164-1008)

=156

S.I. for 2 years = Rs. (156 x 2⁄3 x 2) = Rs. 208

Principal = Rs. (1008 - 208) = Rs. 800

Now, P = 800, T = 2, and S.I. = 208

Rate = (100x208⁄800x2)% = 13%

Answered by Avantikaoni122198
3

Hope it helps.......❤️❤️❤️❤️❤️❤️❤️❤️

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