Question

a printer alloted consecutive integers to all the pages of book starting with 1.in this process,the digits from 0to 9 are used 4893 times.then total number of pages in that book is

Answer 1

Answer:

The total no. of pages will be 1500.

Step-by-step explanation:

Total no. of digits that are used = 4893

The no. of digits  utilized from pg one to nine( 1 digit)

No. of pages = ( 9-1 ) + 1 = 9

Pg contains one digit

No. of digits utilized = 1 x 9 = 9

 

The no. of digits  utilized from pg ten to ninety nine ( double digits)

No. of pg = (99 - 10) + 1 = 90

No. of digits utilized = 2 x 90 = 180

The no. of digits  utilized from pg 100 to 999 (triple digits)

No. of pg = ( 999 - 100 ) + 1 = 900  

No. of digits utilized = 3 x 900 = 2700  

The no. of digits  utilized with 4 digit

Left behind = 4893 - 2700 - 180 - 9 = 2004

No. of pg = 2004 ÷ 4 = 501

Total no. of pg = 501 + 900 + 90 + 9 = 1500