Question

A Priority encoder has 10 active low inputs (D9[high priority]-DO[low priority]) and four active low outputs (A3-A0). What would be the state of the four outputs, if
inputs D4 & D5 are LOW and all other input's are HIGH​

Answer 1

Answer:

101

Explanation:

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Answer 2

If inputs D4 and D5 are low and all other inputs are high, the state of the four outputs of the priority encoder would be:

A3 = 0

A2 = 1

A1 = 0

A0 = 1

• A priority encoder is a digital circuit that converts a binary input to a binary code, such that the highest priority input corresponds to the smallest numerical code.
• In this case, the input D4 has the highest priority as it has the lowest number (D0 is the lowest priority) and input D5 has the second highest priority. Since inputs D4 and D5 are low, they are considered active inputs, and they will be encoded to a binary code based on their priorities.
• The binary code for D4 is 0100 and for D5 is 0010, so the outputs A3-A0 will be 0 1 0 1.

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