Math, asked by TyFox, 2 months ago

A prism and two nets are shown below:

Image of a right triangular prism and 2 nets. The triangle bases have base 4, height 3, and diagonal side 5. The length of the prism from the bases is 8.6. Net A has 3 rectangles in a row. The middle one has sides AC and CD. This middle one has triangle ABC on top and identical triangle below. Net B is the same except that the triangle base ABC is on top of the last rectangle which has sides AC and CD. Units are in inches.

Part A: Which is the correct net for the prism? Explain your answer. (2 points)

Part B: Write the measurements of Sides AB, BC, and CD of the correct net. (4 points)

Part C: What is the surface area of the prism? Show your work. (4 points)

Your answer:
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Answers

Answered by shiniekironaind
9

Answer:

p(x)=3

2n+2

−8x−9 is divisible by 64 …..(1)

When put n=1,

p(1)=3

4

−8−9=64 which is divisible by 64

Let n=k and we get

p(k)=3

2k+2

−8k−9 is divisible by 64

3

2k+2

−8k−9=64m where m∈N …..(2)

Now we shall prove that p(k+1) is also true

p(k+1)=3

2(k+1)+2

−8(k+1)−9 is divisible by 64.

Now,

p(k+1)=3

2(k+1)+2

−8(k+1)−9=3

2

.3

2k+2

−8k−17

=9.3

2k+2

−8k−17

=9(64m+8k+9)−8k−17

=9.64m+72k+81−8k−17

=9.64m+

Answered by reemaenajah10
0

Answer:

p(x)=3

2n+2

−8x−9 is divisible by 64 …..(1)

When put n=1,

p(1)=3

4

−8−9=64 which is divisible by 64

Let n=k and we get

p(k)=3

2k+2

−8k−9 is divisible by 64

3

2k+2

−8k−9=64m where m∈N …..(2)

Now we shall prove that p(k+1) is also true

p(k+1)=3

2(k+1)+2

−8(k+1)−9 is divisible by 64.

Now,

p(k+1)=3

2(k+1)+2

−8(k+1)−9=3

2

.3

2k+2

−8k−17

=9.3

2k+2

−8k−17

=9(64m+8k+9)−8k−17

=9.64m+72k+81−8k−17

=9.64m+

Step-by-step explanation:

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