Question

A prism has a refractive index of 1.414 and an angle of the prism is 30 degrees. Two light rays are parallel as they enter the prism. What is the angle between the rays after they emerge?

Answer 1

Answer:

4.

Explanation:

Given:

A = angle of the prism =

= refractive index of the material of the prism = 1.414

Assume:

a = angle of incidence at the first surface

b = angle of refraction at the first surface

c = angle of incidence at the second surface

= refractive index of air = 1

In order to retrace the path after reflection at the second surface (mirrored surface), the incident ray at the second surface must be perpendicular to the reflecting surface. This means the angle of incidence is zero at the second surface.

i.e.,

So, according to the formula of a prism, we have

Now, using Snell's law of refraction at the first surface, we have

Hence, the angle of incidence should be .

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Answer 2

Answer:

after emergence the parallel rays will still be parallel. Since both pass through the same medium with a denser refractive index, they will both deviate closer to the normal, identically. What matters is the angle of incidence (or the vertical angle at which the ray(s) make on the surface of the prism. Note that refractive index = sin (incident angle) / sin (refracted angle). If you have the incident angle,, using hte given refractive index you can get the refraction angle (arcsin refractive index/ sin(incidence).

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