Question

A prism of refractive index √2 has refracting angle 60°. Angle of MAXIMUM deviation is
Ans is 30°+ sin-¹(√2 sin15°)

Answer 1

Answer Text

45∘

sin−1(2–√sin15∘)

30∘+sin−1(2–√sin15∘)

none

Answer :

B

Solution :

N//a

Answer 2

Explanation:

hope this pic helps thanks for the questionnh