Question

a prism placed in water . the angle of minimum deviation ​

Answer 1

Answer:

The angle of minimum deviation depends on the refractive index of the medium through which the light passes. Since the refractive index of prism glass which is submerged in water is less than the refractive index of the prism in air, there will be a decrease in the angle of minimum deviation.

Explanation:

hope u got it

Answer 2

Answer:

If a prism placed in water, the angle of minimum deviation ​becomes decreases.

Explanation:

A glass prism's refractive index is determined by,

$\mu=\frac{sin(\frac{A+\delta_{min}}{2} )}{sin\frac{A}{2} }$

Where, A is the angle of prism and $\delta_{min}$ is the minimum angle of diffraction.

Hence, from  the above expression we can say that,

$\mu \propto \delta_{min}$

Therefore, if $\delta _{min}$ grows the refractive index rises.

A glass prism's relative refractive index falls when submerged in water. As a result, the minimum deviation angle will also decline.

Hence,

we can say that if a prism placed in water, the angle of minimum deviation ​becomes decreases.

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