A prism whose base is a right angled isosceles triangle has a height 4 cm an
the area of the base is 2 sq.cm. Find its volume and the area of lateral faces
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Given: the base is a right angled triangle with sides a=6cm, b=8cm, c=10cm and T.S.A=156cm
2
. We know that
T.S.A.=2B+Ph=2×
2
1
×8×6+(6+8+10)h=48+24h.
Thus 48+24h=156. This implies that 24h=156−48=108.
Hence h=
24
108
=4.5cm.
Therefore LSA=Ph=(6+8+10)×4.5=24×4.5=108cm
2
.
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